quick메뉴 위아래로 따라다니는 스크롤이 웹표준loose.dtd에서도 되려면? 정보
quick메뉴 위아래로 따라다니는 스크롤이 웹표준loose.dtd에서도 되려면?
본문
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/1999/REC-html401-19991224/loose.dtd">
위의 코드는 웹표준 w3 권장 코드여서 쓰고있는데요. 저렇게 해놓으면
아래의 잘되는 스크롤도 안먹습니다. 어떻게 하면 스크롤이 되게 할까요?
<div id="quick" style="POSITION: absolute; TOP: 250px; Z-INDEX: 1; WIDTH: 77px; HEIGHT: 319px">
<table width="77" height="250" border="0" cellpadding="0" cellspacing="0">
<tr>
<td valign="top"><img src="/images/Quick.gif" width="87" height="319" border="0" usemap="#Map"> </td>
</tr>
</table>
</div>
<script type="text/javascript">
self.onError=null;
currentX = currentY = 0;
whichIt = null;
lastScrollX = 0; lastScrollY = 0;
NS = (document.layers) ? 1 : 0;
IE = (document.all) ? 1: 0;
function MoveQuickMenu() {
if(IE) {
diffY = document.body.scrollTop;
diffX = 0;
}
if(NS) { diffY = self.pageYOffset; diffX = self.pageXOffset; }
if(diffY != lastScrollY) {
percent = .1 * (diffY - lastScrollY);
if(percent > 0) percent = Math.ceil(percent);
else percent = Math.floor(percent);
if(IE) document.all.quick.style.pixelTop += percent;
if(NS) document.quick.top += percent;
lastScrollY = lastScrollY + percent;
}
if(diffX != lastScrollX) {
percent = .1 * (diffX - lastScrollX);
if(percent > 0) percent = Math.ceil(percent);
else percent = Math.floor(percent);
if(IE) document.all.quick.style.pixelLeft += percent;
if(NS) document.quick.top += percent;
lastScrollY = lastScrollY + percent;
}
}
if(NS || IE) action = window.setInterval("MoveQuickMenu()",1);
</script>
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